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Array30.py
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74 lines (72 loc) · 2.67 KB
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'''
功能:有效的数独
来源:https://leetcode-cn.com/explore/interview/card/top-interview-questions-easy/1/array/30/
重点:使用集合判定是否有重复元素
作者:薛景
最后修改于:2019/07/13
'''
# 该方案战胜 95.94 % 的 python3 提交记录
class Solution:
def isValidSudoku(self, board: list) -> bool:
# 判断每行是否有重复
for i in range(9):
set1 = set()
for j in range(9):
if board[i][j]!='.':
if board[i][j] in set1:
return False
else:
set1.add(board[i][j])
# 判断每列是否有重复
for i in range(9):
set2 = set()
for j in range(9):
if board[j][i]!='.':
if board[j][i] in set2:
return False
else:
set2.add(board[j][i])
# 定义一个函数,用来验证自x,y坐标开始的那个9宫格内是否有重复
def isValid(x,y):
set3 = set()
for i in range(x,x+3):
for j in range(y,y+3):
if board[i][j]!='.':
if board[i][j] in set3:
return False
else:
set3.add(board[i][j])
return True
# 从9个顶点开始验证9个不同的9宫格的数字是否有重复
start = [(0,0),(0,3),(0,6),(3,0),(3,3),(3,6),(6,0),(6,3),(6,6)]
for item in start:
if not isValid(item[0],item[1]):
return False
# 如果上述验证过程中,都没有返回False,即没有重复数字,则返回True
return True
# 以下是本地测试代码,提交时只需复制上面的代码块即可
solution = Solution()
board = [
["5","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
print(solution.isValidSudoku(board))
board = [
["8","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
print(solution.isValidSudoku(board))