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9_Palindrome_Number.cpp
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92 lines (81 loc) · 2.17 KB
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/*
Easy.
9. Palindrome Number
Given an integer x, return true if x is a palindrome, and false otherwise.
------------------
Example 1:
Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.
------------------
Example 2:
Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
-----------------
Example 3:
Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
=================
Constraints:
-231 <= x <= 231 - 1
Follow up: Could you solve it without converting the integer to a string?
*/
#include <cassert>
#include <string>
using std::string;
class Solution {
public:
bool isPalindrome(int x) {
if (x < 0) {
return false;
}
if (x == 0) {
return true;
}
const std::string x_string = std::to_string(x);
for (size_t index = 0; index < x_string.size()/2; ++index ) {
if (x_string[index] != x_string[x_string.size()-index-1]) {
return false;
}
}
return true;
}
};
class Solution2 { // without converting the integer to a std::string
public:
bool isPalindrome(const int x) {
if (x < 0) {
return false;
}
if (x == 0) {
return true;
}
if (x%10 == 0) { // the last digit of the number is zero
return false;
}
long long reversed = 0;
int x_copy = x;
while (x_copy > 0) {
reversed = reversed*10 + x_copy % 10;
x_copy /= 10;
}
return (long long)x == reversed;
}
};
int main() {
Solution s;
assert(true == s.isPalindrome(151));
assert(false == s.isPalindrome(-151));
assert(true == s.isPalindrome(0));
assert(false == s.isPalindrome(1511));
assert(false == s.isPalindrome(10));
Solution2 s2;
assert(true == s2.isPalindrome(151));
assert(false == s2.isPalindrome(-151));
assert(true == s2.isPalindrome(0));
assert(false == s2.isPalindrome(1511));
assert(false == s2.isPalindrome(10));
return 0;
}