Cannot use IEnumerable<T> as a TSuccess Type in Try

[freneza]

I created a method where I'd like to return an IEnumerable, but compiler cannot implicitly convert it to try<Exception, IEnumerable>. My code is just:

    public Try<Exception, IEnumerable<Person>> GetAll()
    {
        using (IDbConnection connection = new SqlConnection(ConnectionString))
        {
            try
            {
                return connection.Query<Person>(QueryGetAll); 
            }
            catch(Exception ex)
            {
                return ex;
            }
        }
    }

[mayconbeserra]

@freneza you are having this issue because of the return statement.

GetAll() should return a Try<Exception, IEnumerable> type.

e.g.
return Try.Run( () => connection.Query<Person>(QueryGetAll));

If you look @ElemarJR 's implementation of Try.Run, it's returning Exception and TSuccess

[LuanNunes]

@freneza you can try this:

return connection.Query(QueryGetAll).AsEnumerable();

preserving the deferred mode.
Regards,