array_operations

Remove all exclamation marks from the end of sentence.
Examples
remove("Hi!") === "Hi"
remove("Hi!!!") === "Hi"
remove("!Hi") === "!Hi"
remove("!Hi!") === "!Hi"
remove("Hi! Hi!") === "Hi! Hi"
remove("Hi") === "Hi"

def remove(s):
    if s[-1]=='!':
        i = 1
        while s[-i]=='!':
            i+=1
        i = i-1
        return s[:-i]
    else:
        return s


Your task is to find the first element of an array that is not consecutive.
E.g. If we have an array [1,2,3,4,6,7,8] then 1 then 2 then 3 then 4 are all consecutive but 6 is not, so that's the first non-consecutive number.
If the whole array is consecutive then return null or Nothing.
The array will always have at least 2 elements1 and all elements will be numbers. The numbers will also all be unique and in ascending order. The numbers could be positive or negative and the first non-consecutive could be either too!

def first_non_consecutive(arr):
    for i in range(int(len(arr)-1)):
        if abs(arr[i]-arr[i+1])>1:
            return arr[i+1]