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I give a try to read the arXiv paper of Calandriello et al. 2017 but failed to understand the link between the actual paper formula in section 3, Sequential RLS Sampling 👇
and the code implementation of compute_tau:
def compute_tau(centers_dict: CentersDictionary,
X: np.ndarray,
similarity_func: callable,
lam_new: float,
force_cpu=False):
.
.
.
diag_norm = np.asarray(similarity_func.diag(X))
# (m x n) kernel matrix between samples in dictionary and dataset X
K_DU = xp.asarray(similarity_func(centers_dict.X, X))
# The estimator proposed in Calandriello et al. 2017 is
# diag(XX' - XX'S(SX'XS + lam*I)^(-1)SXX')/lam
# Here for efficiency we collect an S inside the inverse and compute
# diag(XX' - XX'(X'X + lam*S^(-2))^(-1)XX')/lam
# note that in the second term, we take care of dropping the rows/columns of X associated
# with 0 entries in S
U_DD, S_DD, _ = np.linalg.svd(xp.asnumpy(similarity_func(centers_dict.X, centers_dict.X)
+ lam_new * np.diag(centers_dict.probs)))
U_DD, S_root_inv_DD = __stable_invert_root(U_DD, S_DD)
E = xp.asarray(S_root_inv_DD * U_DD.T)
# compute (X'X + lam*S^(-2))^(-1/2)XX'
X_precond = E.dot(K_DU)
# the diagonal entries of XX'(X'X + lam*S^(-2))^(-1)XX' are just the squared
# ell-2 norm of the columns of (X'X + lam*S^(-2))^(-1/2)XX'
tau = (diag_norm - xp.asnumpy(xp.square(X_precond, out=X_precond).sum(axis=0))) / lam_new 👈Like,
- Is
X'Xreflect the kernel matrix$\mathbf{K}_t=\boldsymbol{\Phi}_t^{\top}\boldsymbol{\Phi}_t$ ? And what about$XX'$ ? - I couldn't understand what is
X_precondhere and whysvddecomposition needed. - In section 3 there was the definition of a dictionary, "we redefine a dictionary as a collection
$\mathcal{I}={(i,\widetilde{p_i},q_i)}$ , where$i$ is the index of the point$x_i$ stored in the dictionary,$\widetilde{p_i}$ tracks the probability used to sample it, and$q_i$ is the number of copies (multiplicity) of i." - here I couldn't understand the$q_i$ - Overall, I feel, I didn't understand the
EXPANDandSHRINKfor Algorithm 1 intuitively. It will be a great help if you comment something on this.
It would be greatly appreciated if you could assist me in resolving this matter.
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