problem_2.md

title	Top Student

Problem Statement

Implement the function top_student(students: list) -> dict that takes a list of dictionaries where each dictionary contains 'name' and 'marks' of a student. Return a dictionary with the following keys:

• 'average': the average marks rounded to 2 decimal places.
• 'topper': the name of the student with the highest marks.

Example

students = [ {"name": "lucky", "marks": 85}, {"name": "Rocky", "marks": 92}, {"name": "Chocky", "marks": 78} ] top_student(students) # Output: {"average": 85.0, "topper": "Rocky"}

Solution

py3 test.py -r 'python test.py' def top_student(students: list) -> dict: ''' Find the average marks and the student with the highest marks. Arguments: students: list - a list of dictionaries containing 'name' and 'marks'. Return: dict - a dictionary with 'average' and 'topper'. ''' ... average = round(sum(s['marks'] for s in students) / len(students), 2) topper = max(students, key=lambda x: x['marks'])['name'] return {'average': average, 'topper': topper}

{% include '../function_type_and_modify_check_suffix.py.jinja' %}

Public Test Cases

Input 1

students = [ {"name": "Johny", "marks": 70}, {"name": "Dony", "marks": 90}, {"name": "Smithy", "marks": 80} ] is_equal( top_student(students), {"average": 80.0, "topper": "Dony"} )

Output 1

{"average": 80.0, "topper": "Dony"}

Private Test Cases

Input 1

students = [ {"name": "Ammu", "marks": 88}, {"name": "Evuram", "marks": 92} ] is_equal( top_student(students), {"average": 90.0, "topper": "Evuram"} )

Output 1

{"average": 90.0, "topper": "Evuram"}

Input 2

students = [ {"name": "Manvendra", "marks": 70}, {"name": "Lokendra", "marks": 86} ] is_equal( top_student(students), {"average": 78.0, "topper": "Lokendra"} )

Output 2

{"average": 78.0, "topper": "lokendra"}