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constructBinaryTreefromInorderandPostorderTraversal.cpp
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39 lines (37 loc) · 1.51 KB
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// Source: https://leetcode.com/problems/construct-binary-tree-from-inorder-and-postorder-traversal/
// Author: Miao Zhang
// Date: 2021-01-18
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* buildTree(vector<int>& inorder, vector<int>& postorder) {
if (inorder.empty() && postorder.empty()) return nullptr;
return buildTreeCore(inorder, postorder, 0, inorder.size() - 1, 0, postorder.size() - 1);
}
TreeNode* buildTreeCore(vector<int>& inorder, vector<int>& postorder, int in_left, int in_right, int post_left, int post_right) {
if (post_right < 0) return nullptr;
int val = postorder[post_right];
int in_pos;
if (in_left > in_right) return nullptr;
for (int i = in_left; i <= in_right; i++) {
if (inorder[i] == val) {
in_pos = i;
break;
}
}
TreeNode* root = new TreeNode(val);
root->left = buildTreeCore(inorder, postorder, in_left, in_pos - 1, post_left, post_left + in_pos - in_left - 1);
root->right = buildTreeCore(inorder, postorder, in_pos + 1, in_right, post_left + in_pos - in_left, post_right - 1);
return root;
}
};