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constructBinaryTreefromPreorderandInorderTraversal.cpp
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40 lines (37 loc) · 1.44 KB
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// Source: https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/
// Author: Miao Zhang
// Date: 2021-01-18
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) {
if (preorder.empty() && inorder.empty()) return nullptr;
return buildTreeCore(preorder, inorder, 0, 0, inorder.size() - 1);
}
TreeNode* buildTreeCore(vector<int>& preorder, vector<int>& inorder, int pre_pos, int in_left, int in_right) {
if (pre_pos >= preorder.size()) return nullptr;
int val = preorder[pre_pos];
int in_pos;
if (in_left > in_right) return nullptr;
for (int i = in_left; i <= in_right; i++) {
if (inorder[i] == val) {
in_pos = i;
break;
}
}
TreeNode* root = new TreeNode(val);
root->left = buildTreeCore(preorder, inorder, pre_pos + 1, in_left, in_pos - 1);
root->right = buildTreeCore(preorder, inorder, pre_pos + in_pos - in_left + 1, in_pos + 1, in_right);
return root;
}
};