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minimumIncompatibility.cpp
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30 lines (29 loc) · 1.13 KB
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// Source: https://leetcode.com/problems/minimum-incompatibility/
// Author: Miao Zhang
// Date: 2021-05-27
class Solution {
public:
int minimumIncompatibility(vector<int>& nums, int k) {
int n = nums.size();
int m = n / k;
vector<vector<int>> dp(1 << n, vector<int>(16, INT_MAX / 2));
for (int i = 0; i < n; i++) dp[1 << i][i] = 0;
for (int mask = 0; mask < 1 << n; mask++) {
for (int i = 0; i < n; i++) {
if ((mask & (1 << i)) == 0) continue;
for (int j = 0; j < n; j++) {
if (mask & (1 << j)) continue;
int t = mask | (1 << j);
if (__builtin_popcount(mask) % m == 0) {
dp[t][j] = min(dp[t][j], dp[mask][i]);
} else if (nums[j] > nums[i]) {
dp[t][j] = min(dp[t][j],
dp[mask][i] + nums[j] - nums[i]);
}
}
}
}
int res = *min_element(begin(dp[(1 << n) - 1]), end(dp[(1 << n) - 1]));
return res == INT_MAX / 2 ? -1 : res;
}
};