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sudokuSolver.py
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97 lines (90 loc) · 3.19 KB
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#! /usr/bin/env python3
# -*- coding: utf-8 -*-
# Source: https://leetcode.com/problems/sudoku-solver/
# Author: Miao Zhang
# Date: 2021-01-08
class Solution:
def solveSudoku(self, board: List[List[str]]) -> None:
"""
Do not return anything, modify board in-place instead.
"""
def isValid(x, y):
val = board[x][y]
board[x][y] = 'X'
for i in range(9):
if board[i][y] == val:
return False
for j in range(9):
if board[x][j] == val:
return False
for i in range(3):
for j in range(3):
if board[(x // 3) * 3 + i][(y // 3) * 3 + j] == val:
return False
board[x][y] = val
return True
def dfs(board):
for i in range(9):
for j in range(9):
if board[i][j] == '.':
for num in range(1, 10):
board[i][j] = str(num)
if isValid(i, j) and dfs(board):
return True
board[i][j] = '.'
return False
return True
dfs(board)
# Time Limit Exceeded
class Solution:
def solveSudoku(self, board: List[List[str]]) -> None:
"""
Do not return anything, modify board in-place instead.
"""
row = [set() for _ in range(9)]
col = [set() for _ in range(9)]
cell = [set() for _ in range(9)]
# init env
for i in range(9):
for j in range(9):
if board[i][j] != '.':
row[i].add(board[i][j])
col[j].add(board[i][j])
cell[3 * (i // 3) + j // 3].add(board[i][j])
def dfs(i, j):
'''
backtrace
from left to right, from top to down
i,j->i,j+1->i,8->i+1,0
'''
if board[i][j] != '.':
if i == 8 and j == 8:
self.flag = True
return
elif j < 8:
dfs(i, j + 1)
else:
dfs(i + 1, 0)
else:
for num in range(10):
num = str(num)
if num not in row[i] and num not in col[j] and num not in cell[3 * (i // 3) + j // 3]:
board[i][j] = num
row[i].add(num)
col[j].add(num)
cell[3 * (i // 3) + j // 3].add(num)
if i == 8 and j == 8:
self.flag = True
return
elif j < 8:
dfs(i, j + 1)
else:
dfs(i + 1, 0)
if flag:
return
board[i][j] = '.'
row[i].remove(num)
col[j].remove(num)
cell[3 * (i // 3) + j // 3].remove(num)
flag = False
dfs(0, 0)