Task - Armstrong and Special Number

[akash-coded]

1. WAF to check if a number is an Armstrong number or not.

2. WAF to check if a number is a Special (Krishnamurthy) number or not.

Explanation:

[ramprasana]

function armstrongNumber() {
let num1 = prompt("Enter the first value",0);
let n1 = Number(num1);
let sum = 0;

while(n1 > 0) {
    let digit = n1 %  10;
    sum = sum + digit ** 3;
    n1 = Math.trunc(n1 / 10);
    // console.log(n1);
}
console.log(sum);
if(sum === n1) {
    return true;
} else {
    return false;
}

}

[YashShekhar]

function armstrong() {
var number = parseInt(
prompt("Enter any number to check if it is an armstrong number :")
);
var originalNumber = number;
var sumNumber = 0;
// var digit = 0;
while (number != 0) {
var digit = number % 10;
console.log(digit);
sumNumber += Math.pow(digit, 3);
number = parseInt(number / 10);
}
console.log(sumNumber == originalNumber);

if (originalNumber == sumNumber)
    document.write("It is an armstrong number");
else document.write("It is not an armstrong number");

}

[koushik3107]

let sum=0;

number = prompt("Enter a number");
let temp = number;

while(temp>0){
let remainder =temp%10;
sum += remainderremainderremainder;

temp = parseInt(temp/10);

}

if (sum==number){
console.log("It is an armstrong number");

}
else{
console.log("It is not an armstrong number");
}

[pooja2apr]

<script> const number = prompt("Enter a number"); const numberOfDigits = number.length; let sum = 0; // create a temporary variable let temp = number; while (temp > 0) { let remainder = temp % 10; sum += remainder ** numberOfDigits; // removing last digit from the number temp = parseInt(temp / 10); // convert float into integer } if (sum == number) { console.log(`${number} is an Armstrong number`); } else { console.log(`${number} is not an Armstrong number.`); } </script>

[akash-coded]

• the variable temp can be better renamed to originalNum
• similarly, remainder can be renamed to digit

[Meharafsha]

function Armstrong()
{
var flag,number,remainder,addition = 0;
number = Number(document.getElementById("N").value);

	flag = number;
	while(number > 0)
	{
		remainder = number%10;
		addition = addition + remainder*remainder*remainder;
		number = parseInt(number/10);
	}

	if(addition == flag)
	{
		window.alert("-The inputed number is Armstrong");
	}
	else
	{
		window.alert("-The inputed number is not Armstrong");
	}
}

[akash-coded]

• the variable flag can be better renamed to originalNum
• remainder can be renamed to digit

[nidhiprajapati2018]

   let sum = 0;
    const number = prompt('Enter a three-digit positive integer: ');
    let temp = number;
    while (temp > 0) {

        let remainder = temp % 10;

        sum += remainder * remainder * remainder;
        temp = parseInt(temp / 10);
    }

    if (sum == number) {
        console.log(`${number} is an Armstrong number`);
    }
    else {
        console.log(`${number} is not an Armstrong number.`);

[akash-coded]

• the variable temp can be better renamed to originalNum
• similarly, remainder can be renamed to digit

[nidhiprajapati2018]

Sure, Thanks

[YashShekhar]

Task 2:
function factorial() {
var number = parseInt(prompt("Enter any number to find its factorial :"));

var result = 1;
if (number >= 0) {
    while (number != 0) {
        result *= number;
        number -= 1;
    }
    document.write(result);
} else {
    document.write("Positive number expected!!");
}

}

[Mohini899]

let sum = 0;
const number = prompt('Enter a three-digit positive integer: ');

let temp = number;
while (temp > 0) {
let remainder = temp % 10;

sum += remainder * remainder * remainder;


temp = parseInt(temp / 10); 

}

if (sum == number) {
console.log(${number} is an Armstrong number);
}
else {
console.log(${number} is not an Armstrong number.);
}

[Wgjamia]

const number1 = prompt('Enter a First integer: ');
const number2 = prompt('Enter a Second integer: ');
const number3 = prompt('Enter a Third integer: ');

function ArmNumFunc(num1){
let sum = 0;
let n = num1;
while (n > 0) {
let remainder = n % 10;
sum += remainder * remainder * remainder;
n = parseInt(n / 10);
}
return sum;
}
var coll = ArmNumFunc(number1) + ArmNumFunc(number2) +ArmNumFunc(number3);
console.log(coll);
if (coll == parseInt(number1+number2+number3)){
console.log(${number1} ${number2} ${number3} is an Armstrong number.);
}else{
console.log(${number1} ${number2} ${number3} iis not an Armstrong number.);
}

[akash-coded]

The implementation takes three numbers as input, whereas the question is to check for a single number if it is Armstrong or not.

[ramprasana]

Task - Special Number

`function factorialize(num) {
var result = num;
if(0 === num || 1 === num)
return 1;
while(num > 1) {
num--;
result = result * num;
}
return result;
}

function specialNumber() {
var num1 = prompt("Enter the number to check for special number :");
var n1 = Number(num1);
var sum = 0;
while(n1 > 0) {
let digit = n1 % 10;
sum = sum + factorialize(digit);
n1 = Math.trunc(n1 / 10);
}

console.log(sum);
if(num1 == sum) {
    console.log("It is speical number")
} else {
    console.log("It is not speical number")
}

}`

[somitadubey]

function armstrom() {
let sum = 0
numb = prompt('Enter a number ')
let n1 = number(numb)
while (n1 > 0) {

            let a = n1 % 10;
            res = res + a ** 3;
            n1 = math.trunc(n1 / 10);
            console.log(n1);
        }
        console.log(res);
        if (res == n1) {
            return true;
        } else {
            return false;
        }

[Sreelakshmi-cs]

number=prompt("Enter the number");
let temp=number;
let sum=0;
while(temp>0)
{
digit=temp%10;
sum=sum+(digit)(digit)(digit);
temp=temp/10;
}
if(sum==number)
{
console.log("The number is an amstrong");
}
else{
console.wrire("the number is not amstrong");
}

[Wgjamia]

Hi Akash
I'm try to compete the task Krishnamurthy number , but I have summation extra where run the task

function fact(num1)
{
var f = 1;
for(var i=1; i<=num1; i++) {
f *= i;
}
return f;
}
function isKrishnamurthy(num1){
var res = false;
var sum = 0;
var t = 0;
var n = num1;

while(n != 0) {
    t = n % 10;

    sum += fact(t);
    console.log(fact(t))
    n /= 10;
}
console.log(sum);
if(sum == num1)
    res= true; 

return res;

}

var numb1 = prompt('Enter the value of range');
var result = false;

result = isKrishnamurthy(parseInt(numb1));

if(result)
console.log(${numb1} is a Krishnamurthy number.);
else
console.log(${numb1} is not a Krishnamurthy number.);

kindly your help to find this issue.

[akash-coded]

Here is the rectified code:

function fact(num1) {
  var f = 1;
  for (var i = 1; i <= num1; i++) {
    f *= i;
  }
  return f;
}

function isKrishnamurthy(num1) {
  var res = false;
  var sum = 0;
  var n = num1;

  while (n != 0) {
    var digit = n % 10;
    n = parseInt(n / 10);
    sum += fact(digit);
  }

  if (sum == num1) res = true;

  console.log(sum);
  return res;
}

var numb1 = prompt("Enter the value of range: ");
var result = false;

result = isKrishnamurthy(parseInt(numb1));

if (result) console.log(`${numb1} is a Krishnamurthy number.`);
else console.log(`${numb1} is not a Krishnamurthy number.`);

I have rectified a couple of syntax errors and the main issue was not using parseInt while dividing n by 10. It led to floating-point division, which caused an extra iteration even after n became less than 1.