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CookingSchedule.java
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174 lines (151 loc) · 4.42 KB
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package problems.codechef;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.Collections;
import java.util.HashMap;
import java.util.TreeMap;
import java.util.concurrent.ConcurrentHashMap;
/**
* Created by hardCode on 3/12/2017.
*/
public class CookingSchedule {
static char[]a=new char[1000001];
public static void main(String[] args) throws IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int t,n,k;
String[]s;
String s1;
t=Integer.parseInt(br.readLine());
while (t-->0){
s=br.readLine().split("\\s");
n = Integer.parseInt(s[0]);
k = Integer.parseInt(s[1]);
s1=br.readLine();
for (int i = 0; i < n; i++) {
if ("1".equals(s1.charAt(i)+""))
a[i] = '1';
else
a[i]='0';
}
System.out.println(solve1(a, n, k));
}
}
private static int solve1(char[] a, int n, int k) {
if (oneStart(a,n)<=k || zeroStart(a,n)<=k)
return 1;
return binarySearch(a,n,k);
}
private static int binarySearch(char[] a, int n, int k) {
int start=2,end=n,mid,minLength=Integer.MAX_VALUE;
while (start<=end){
mid=(start+end)/2;
boolean flag=isSegmentPossible(a,n,k,mid);
if (flag)
{
minLength=Integer.min(minLength,mid);
end=mid-1;
}
else
start=mid+1;
}
return minLength;
}
private static boolean isSegmentPossible(char[] a, int n, int maxFlips, int mid) {
int oneCount,zeroCount,requiredFlips;
oneCount=zeroCount=requiredFlips=0;
if (a[n-1]=='0')
a[n]='1';
else a[n]='0';
if (a[0]=='1')
oneCount=1;
else zeroCount=1;
for (int i = 1; i <=n; i++) {
if (a[i]=='1'){
oneCount++;
if (a[i]!=a[i-1]){
requiredFlips+=zeroCount/(mid+1);
zeroCount=0;
}
}
else {
zeroCount++;
if (a[i]!=a[i-1]){
requiredFlips+=oneCount/(mid+1);
oneCount=0;
}
}
}
if (requiredFlips<=maxFlips)return true;
return false;
}
private static int oneStart(char[] a, int n) {
int flips=0;
for (int i = 0; i < n; i++) {
if ((i&1)==1){
if (a[i]=='1')
flips++;
}
else {
if (a[i]=='0')
flips++;
}
}
return flips;
}
private static int zeroStart(char[] a, int n) {
int flips=0;
for (int i = 0; i < n; i++) {
if ((i&1)==1){
if (a[i]=='0')
flips++;
}
else {
if (a[i]=='1')
flips++;
}
}
return flips;
}
//Below code is the solution that takes exponential time
private static int solve(char[] a, int n, int k) {
return maximumBlockSize(a, n, k);
}
private static int maximumBlockSize(char[] a, int n, int k) {
if (n==0 || k==0){
return longestSegment(a);
}
char temp[]=new char[a.length];
System.arraycopy(a,0,temp,0,a.length);
if (a[n - 1] == '0') {
temp[n-1]='1';
}
else {
temp[n-1]='0';
}
int changed=maximumBlockSize(temp, n - 1, k - 1);
int unchanged=maximumBlockSize(a, n - 1, k);
return Integer.min(changed,unchanged);
}
static int longestSegment(char[]a){
int maxZero=0,maxOne,zeros,ones;
maxOne=zeros=ones=0;
int n=a.length;
for (int i = 0; i < n; i++) {
if (a[i]=='0'){
maxOne=Integer.max(maxOne,ones);
ones=0;
zeros++;
}
if (a[i]=='1'){
maxZero=Integer.max(maxZero,zeros);
zeros=0;
ones++;
}
}
maxOne=Integer.max(maxOne,ones);
maxZero=Integer.max(maxZero,zeros);
return Integer.max(maxOne,maxZero);
}
}