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ConstructBinaryTreeFromPreorderAndInorderTraversal.py
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58 lines (45 loc) · 1.36 KB
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from typing import List
# Definition for a binary tree node.
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution:
def buildTree(self, preorder: List[int], inorder: List[int]) -> TreeNode:
if not preorder:
return None
if len(preorder) == 1:
return TreeNode(preorder[0])
root = TreeNode(preorder[0])
rootIndexInInorder = inorder.index(root.val)
left_inorder = inorder[:rootIndexInInorder]
right_inorder = inorder[rootIndexInInorder+1:]
left_preorder = preorder[1:rootIndexInInorder+1]
right_preorder = preorder[rootIndexInInorder+1:]
root.left = self.buildTree(left_preorder, left_inorder)
root.right = self.buildTree(right_preorder, right_inorder)
return root
# Recursive postorderTraversal
def postorderTraversal(root: TreeNode) -> List[int]:
if root is None:
return []
result = []
result += postorderTraversal(root.left)
result += postorderTraversal(root.right)
result.append(root.val)
return result
########
# Test #
########
preorder = [3, 9, 20, 15, 7]
inorder = [9, 3, 15, 20, 7]
root = Solution().buildTree(preorder, inorder)
# expected:
# 3
# / \
# 9 20
# / \
# 15 7
print(postorderTraversal(root))
# expected: [9, 15, 7, 20, 3]