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Question20.java
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85 lines (73 loc) · 1.7 KB
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import java.util.Arrays;
/***
*
*
* n! means n × (n − 1) × ... × 3 × 2 × 1
*
* For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800, and the sum of the
* digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.
*
* Find the sum of the digits in the number 100!
*
* @author chz
*
*/
public class Question20 {
static int res[];
static int curPos;
public static void mul(int val) {
String valStr = String.valueOf(val);
char valArr[] = valStr.toCharArray();
// System.out.println("val: " + Arrays.toString(valArr));
int len = valArr.length;
int tmpArr[][] = new int[len][curPos + 1];
// System.out.println(Arrays.deepToString(tmpArr));
int i = 0, j = 0;
int carryOver;
for (i = 0; i < len; i++) {
carryOver = 0;
for (j = 0; j < curPos; j++) {
int tmp = res[j] * (valArr[len - i - 1] - '0') + carryOver;
tmpArr[i][j] = tmp % 10;
carryOver = tmp / 10;
}
if (carryOver != 0) {
tmpArr[i][curPos] = carryOver;
carryOver = 0;
}
}
Arrays.fill(res, 0);
for (i = 0; i < len; i++) {
// res[i] = 0;
carryOver = 0;
for (j = 0; j < curPos; j++) {
int tmp = res[i + j] + tmpArr[i][j] + carryOver;
res[i + j] = tmp % 10;
carryOver = tmp / 10;
}
if (carryOver != 0) {
res[i + j] = carryOver;
carryOver = 0;
}
}
curPos = i + j;
}
private static void init(int num) {
res = new int[num * 10];
res[0] = 1;
curPos = 1;
}
public static void main(String[] args) {
int number = 1000;
init(number);
int i = 0;
for (i = 1; i <= number; i++) {
mul(i);
}
int sum = 0;
for (i = 0; i < curPos; i++) {
sum += res[i];
}
System.out.println("sum of each digit of " + number + "! is :" + sum);
}
}