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//
// searchRange.h
// bsearch
//
// Created by junlongj on 2019/8/26.
// Copyright © 2019 junl. All rights reserved.
//
#ifndef searchRange_hpp
#define searchRange_hpp
#include <stdio.h>
#include <vector>
/*
34.在排序数组中查找元素的第一个和最后一个位置
给定一个按照升序排列的整数数组 nums,和一个目标值 target。找出给定目标值在数组中的开始位置和结束位置。
你的算法时间复杂度必须是 O(log n) 级别。
如果数组中不存在目标值,返回 [-1, -1]。
示例 1:
输入: nums = [5,7,7,8,8,10], target = 8
输出: [3,4]
示例 2:
输入: nums = [5,7,7,8,8,10], target = 6
输出: [-1,-1]
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/find-first-and-last-position-of-element-in-sorted-array
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
*/
namespace leetcod {
using namespace std;
vector<int> searchRange(vector<int>& nums, int target) {
if (nums.empty()) return {-1,-1};
int size = nums.size();
int left=0;
int right=size-1;
while(left<=right){
int mid=left+(right-left)/2;
if (nums[mid] == target){
int s,e;
s = e = mid;
while(s >= 1 &&nums[s-1] == nums[s]){
s--;
}
while(e+1 < size &&nums[e] == nums[e+1]){
e++;
}
return {s,e};
}else if (nums[mid] < target){
left=mid+1;
}else{
right=mid-1;
}
}
return {-1,-1};
}
}
#endif /* searchRange_hpp */