Q3data_processing_io.md

title	Process Student Marks
tags	data processing student marks

Problem Statement

Write a function process_student_marks that processes student marks and performs the following operations:

1. Read the number of students (n) and their respective names and marks.
2. Compute the average mark (rounded to 2 decimal places).
3. Determine the student(s) with the highest mark.
4. Print the results:
   • Each student's name and mark, sorted alphabetically by name.
   • The average mark.
   • The names of the top-performing students (alphabetically sorted in case of a tie).

Input

The first line contains an integer n, the number of students.
The next n lines each contain a student's name and mark, separated by a space.

Output

The output should include:

1. Each student's name and mark in alphabetical order.
2. The average mark (rounded to 2 decimal places).
3. The names of the top-performing students.

Solution

<prefix>
def process_student_marks(n: int) -> str:
    '''
    Process student marks and generate results based on the given rules.
    
    Arguments:
    n: int - Number of students.
    
    Returns:
    str - Formatted string with student details, average mark, and top performers.
    '''
</prefix>
<template>
    <sol>
    # Initialize dictionary to store student marks
    student_marks = {}
    # Read input and store marks
    for _ in range(n):
        name, mark = input().split()
        mark = float(mark)
        student_marks[name] = mark
    # Compute average
    average = round(sum(student_marks.values()) / n, 2)
    # Find top performers
    highest_mark = max(student_marks.values())
    top_performers = sorted([name for name, mark in student_marks.items() if mark == highest_mark])
    # Prepare result
    result = []
    for name in sorted(student_marks.keys()):
        result.append(f"{name}: {student_marks[name]:.2f}")
    result.append(f"average: {average:.2f}")
    result.append(f"top_performers: {', '.join(top_performers)}")
    return "\n".join(result)
    </sol>
    <los>pass</los>
</template>
<suffix>
n = int(input())
print(process_student_marks(n))
</suffix>
<suffix_invisible>

</suffix_invisible>

Public Test Cases

Input 1

3
Alice 85
Bob 90
Charlie 85

Output 1

Alice: 85.00
Bob: 90.00
Charlie: 85.00
average: 86.67
top_performers: Bob

Input 2

4
Daisy 78
Ella 95
Fiona 95
George 88

Output 2

Daisy: 78.00
Ella: 95.00
Fiona: 95.00
George: 88.00
average: 89.00
top_performers: Ella, Fiona

Input 3

2
Hank 75
Ivy 85

Output 3

Hank: 75.00
Ivy: 85.00
average: 80.00
top_performers: Ivy

Private Test Cases

Input 1

5
John 60
Jane 95
Jack 60
Jill 80
Jerry 95

Output 1

Jack: 60.00
Jane: 95.00
Jerry: 95.00
Jill: 80.00
John: 60.00
average: 78.00
top_performers: Jane, Jerry

Input 2

3
Kim 70
Liam 85
Mia 85

Output 2

Kim: 70.00
Liam: 85.00
Mia: 85.00
average: 80.00
top_performers: Liam, Mia

Input 3

4
Nancy 90
Oscar 85
Paul 85
Quincy 90

Output 3

Nancy: 90.00
Oscar: 85.00
Paul: 85.00
Quincy: 90.00
average: 87.50
top_performers: Nancy, Quincy