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Inversion.cpp
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102 lines (91 loc) · 2.33 KB
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/*
AUTHOR : Peeyush Yadav
Problem : https://www.hackerrank.com/challenges/insertion-sort
*/
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define f(a,b,c) for(int a=b;a<c;a++)
#define s(x) scanf("%d",&x);
#define sl(x) scanf("%lld",&x);
#define p(x) printf("%d\n",x);
#define p2(x,y) printf("%d %d\n",x,y);
#define pl(x) printf("%lld\n",x);
#define pl2(x,y) printf("%lld %lld\n",x,y);
#define p1d(a,n) for(int ix=0;ix<n;ix++) printf("%d ",a[ix]); printf("\n");
#define p2d(a,n,m) for(int ix=0;ix<n;ix++){ for(int jx=0;jx<m;jx++) printf("%d ",a[ix][jx]); printf("\n");}
void input(){
#ifdef Megamind
#define DEBUG
#define TRACE
freopen("inp.txt","r",stdin);
//freopen("out1.txt","w",stdout);
#endif
}
#ifdef TRACE
#define trace(x) cerr<<__FUNCTION__<<":"<<__LINE__<<": "#x" = "<<x<<endl;
#define trace2(x,y) cerr<<__FUNCTION__<<":"<<__LINE__<<": "#x" = "<<x<<" | "#y" = "<<y<<endl;
#define trace3(x,y,z) cerr<<__FUNCTION__<<":"<<__LINE__<<": "#x" = "<<x<<" | "#y" = "<<y<<" | "#z" = "<<z<<endl;
#else
#define trace(x)
#define trace2(x,y)
#define trace3(x,y,z)
#endif
inline ll power(ll a, ll b, ll m) {
ll r = 1;
while(b) {
if(b & 1) r = r * a % m;
a = (a * a)% m;
b >>= 1;
}
return r;
}
inline ll power(ll a, ll b) {
ll r = 1;
while(b) {
if(b & 1) r = r * a ;
a = a * a;
b >>= 1;
}
return r;
}
/*........................................................END OF TEMPLATES.......................................................................*/
#define SIZE 123456
ll a[123456],b[SIZE];
int n;
int tree[SIZE];
int read(int ind){
int counter=0;
while(ind > 0){
counter+=tree[ind];
ind-= ind&-ind;
}
return counter;
}
void upd(int ind){
for(int i = ind; i < n+10 ; i+= i&-i) tree[i]++;
}
int main(){
input();
int t,ind;
s(t);
while(t--){
s(n);
ll ans = 0;
f(i,0,n) {
sl(a[i]);
b[i]= a[i];
}
sort(b,b+n);
f(i,0,n){
ind = lower_bound(b,b+n,a[i]) - b;
ans += i - read(ind+1);
upd(ind+1);
}
pl(ans);
memset(tree,0,sizeof(tree));
}
#ifdef Megamind
cerr << "\nTime elapsed : " << 1.0 * clock() / CLOCKS_PER_SEC * 1000 << " ms." << endl;
#endif
}