fizz-buzz.cpp

//question//

Given an integer n, return a string array answer (1-indexed) where:

answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
answer[i] == "Fizz" if i is divisible by 3.
answer[i] == "Buzz" if i is divisible by 5.
answer[i] == i if non of the above conditions are true.
 

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]
Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]
Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
 

Constraints:

1 <= n <= 104


//solution//

class Solution {
public:
    vector<string> fizzBuzz(int n) {
      vector<string> v;
        for(int i=1;i<=n;i++)
        {
            if(i%3==0 && i%5==0)
            {
                v.push_back("FizzBuzz");
            }
            else if(i%3==0)
            {
                v.push_back("Fizz");
            }
            else if(i%5==0)
            {
                v.push_back("Buzz");
            }
            else
            {
                string s="";
                s += to_string(i);
                v.push_back(s);
            }
        }
        return v;
    }
};