Multiprocessing Pipe is missing default value for parameter duplex

[valbaca]

Documentation

The documentation for Pipe reads:

multiprocessing.Pipe([duplex])
Returns a pair (conn1, conn2) of [Connection](https://docs.python.org/3/library/multiprocessing.html#multiprocessing.connection.Connection) objects representing the ends of a pipe.

If duplex is True (the default) then the pipe is bidirectional. If duplex is False then the pipe is unidirectional: conn1 can only be used for receiving messages and conn2 can only be used for sending messages.

The documentation mentions that the default value for duplex is True but it's not listed in the constructor signature of multiprocessing.Pipe([duplex])

It should read:

multiprocessing.Pipe([duplex=True])

Linked PRs

• gh-142067: Add missing default value for param in multiprocessing.Pipe's doc #142109
• [3.14] gh-142067: Add missing default value for param in multiprocessing.Pipe's doc (GH-142109) #142120

[serhiy-storchaka]

Simply multiprocessing.Pipe(duplex=True). Brackets were used to denote an optional parameter (this is not Python syntax), but specifying the default value already makes it optional in Python syntax.

[gpshead]

thanks!