forperfectnum.py

# check if given number is perfect or not
n=int(input('enter a number:'))
sum=0
for num in range(1,n):
    if n%num==0:
        sum+=num 
if sum==n:
    print(f'{n} is a perfect number')

'''
n=6:

Step 1: Input
User inputs 
n=6.

Initialize 
sum=0.

Step 2: Start for loop with 
num ranging from 1 to 
n−1 (i.e., 1 to 5).

Step 3: Iterations inside loop:
num=1:
Check if 6%1==0 (True).

Add 
1 to 
sum → sum=0+1=1.
num=2:

Check if 
6%2==0 (True).
Add 2 to sum →sum=1+2=3.
num=3:

Check if 6%3==0 (True).

Add 
3 to sum → sum=3+3=6.
num=4:

Check if 
6%4==0 (False).
sum remains 6.
num=5:

Check if 6%5==0 (False).
sum remains 
6.

Step 4: Loop ends after 
num=5.

Step 5: Check if sum==n:
sum=6, 

n=6, so condition is True.

Print "6 is a perfect number".
'''