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🧷 문제 링크
https://www.acmicpc.net/problem/20554
🧭 풀이 시간
60분
👀 체감 난이도
✏️ 문제 설명
(0,0)에서 출발하여 상하좌우 중 하나로 구성된 길이 N의 이동 명령을 따라 이동한다.
도착점이 (x,y)가 되기 위해 수정해야 하는 이동 명령의 최솟값을 Q번 구해보자.
🔍 풀이 방법
새로운 도착점 (x,y)는 원래의 도착점 (X,Y)와 체스판 상에서 다른 색 칸에 위치한다면 절대 이동할 수 없다.
또, |x| + |y|가 N보다 크면 어떻게 수정해도 이동할 수 없다.
위 두 경우를 배제하면 답은 (|x-X| + |y-Y|) / 2라고 생각했다.
⏳ 회고
근데 답이 저게 아닌가보다. 왜 아니지? 반례도 못 찾겠음