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🧷 문제 링크
https://www.acmicpc.net/problem/1111
🧭 풀이 시간
50분
👀 체감 난이도
✏️ 문제 설명
숫자 N개가 주어질 때, 규칙은 앞 수*a+b이다.
a, b가 가능한 경우가 여러 개일 경우 A 출력, 다음 수 구할 수 없으면 B 출력, 하나의 경우만 가능하면 다음 수 출력
🔍 풀이 방법
숫자 N이 1, 2, 3이상일 경우로 나눠서 답 구함
a는 첫수랑 두번째 수 나눠서 나온 값, b는 빼서 구함 ㅋ ㅋ
⏳ 회고
그냥 구현인데 와따마 개어려움 ㅋㅋ