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🧷 문제 링크
https://www.acmicpc.net/problem/2011
🧭 풀이 시간
20분
👀 체감 난이도
✏️ 문제 설명
A=1, B=2, ..., Z=26으로 암호화된 숫자 문자열이 주어질 때, 가능한 해석의 경우의 수를 구하는 문제. 결과는 1000000으로 나눈 나머지 출력
🔍 풀이 방법
dp[i] = 앞 i자리를 해석하는 경우의 수
한 자리(1
9) 해석 가능 → dp[i] += dp[i-1]26) 해석 가능 → dp[i] += dp[i-2]두 자리(10
걍 일반적인 dp문제
⏳ 회고
ez