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🧷 문제 링크
https://www.acmicpc.net/problem/2225
🧭 풀이 시간
30분
👀 체감 난이도
✏️ 문제 설명
0부터 N까지 정수 중에서 K개를 골라 더해서 합이 N이 되는 경우의 수를 구하면 된다.
순서가 다르면 다른 경우로 세고, 같은 수를 여러 번 써도 된다.
🔍 풀이 방법
dp[i][j]를 i개의 수로 합이 j가 되는 경우의 수라고 두면 된다.
점화식은
dp[i][j] = dp[i-1][j] + dp[i][j-1]⏳ 회고