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🧷 문제 링크
https://www.acmicpc.net/problem/15486
🧭 풀이 시간
20분
👀 체감 난이도
✏️ 문제 설명
백준이가 n일 후에 퇴사 하려고 n일 동안 최대한 많은 돈을 땡기려고 합니다.
이 때 각 일차별로 걸리는 시간과 그에 대한 보수가 주어졌을 때 퇴사할 때 가장 많이 벌어서 나갈 수 있는 경우의 수익을 구하는 문제입니다.
🔍 풀이 방법
dp를 이용하여 풀었습니다.
1일차에 책정된 일이 3일이 걸리고 보수가 20 이라면 dp[4]=20 으로 저장하고
n일을 순회하면서 dp[현재일+걸리는시간] = math.max(dp[현재일+걸리는시간], dp[현재일]+오늘 받은 일의 보수) 식을 이용했습니다.
⏳ 회고
설명이 조금 어렵게 됐는데 풀어보면 쉽게 풀 수 있는 문제였습니다.