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一个小建议 #1

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21 changes: 11 additions & 10 deletions count.cpp
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Original file line number Diff line number Diff line change
@@ -1,4 +1,4 @@
// count.cpp : �������̨Ӧ�ó������ڵ㡣
// count.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"
Expand All @@ -18,13 +18,13 @@ class Save
};

bool comparison(Save a, Save b) {
//��������>
//降序排列>
return a.number>b.number;
}
string readFileIntoString()
{
ifstream ifile;
//�ȶ��뵽buf
//先读入到buf
ifile.open("d:\\words.txt");
ostringstream buf;
char ch;
Expand All @@ -35,14 +35,15 @@ string readFileIntoString()
return buf.str();
}

//这个函数有点太长了，能否尝试分解一下。而且它的名字也没有准确反应它的功能。
void count(string s)
{
string result;
//record��¼��������ĸ
//record记录单词首字母
int record = 0;
//number��¼���ʳ��ִ���
//number记录单词出现次数
int number = 1;
//ɾ����ͷ�Ŀո�
//删除开头的空格
int i = 0;
int numOfWord = 0;
vector <Save> save(100);
Expand All @@ -51,7 +52,7 @@ void count(string s)
i++;
}
s = s.substr(i, s.size());
//����ת��Ϊ�ո�
//换行转化为空格
for (int i = 0; i < s.size(); i++)
{
if (s[i] == '\n')
Expand All @@ -64,15 +65,15 @@ void count(string s)
{
if (s[i] == 32)
{
//�������ĵ�һ�����ʷ���result��
//把遇到的第一个单词放在result中
result.append(s, record, i - record);
while (s[i] == 32)
{
i++;
}
s = s.substr(i, s.size());
i = 0;
//����s���Ƿ��иõ��ʣ��ҵ����s��ɾ��
//查找s中是否还有该单词，找到则从s中删除
//cout << s << " before "<<endl;
int pos;
while ((pos = s.find(result)) != string::npos)
Expand All @@ -95,7 +96,7 @@ void count(string s)
result = "";
number = 1;
}
//�������һ������
//处理最后一个单词
if (i == s.size() && s != "")
{
//cout << s << " " << "1" << endl;
Expand Down