Update thinkPHPBatchPoc.py#3
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这个i=5判断有问题，如果i=4存在漏洞时，已经写入了i=i+1，所以当i=5时，就会生成no vulnerable告警，但flag已经变成了true，flag意义已经不存在了，所以应该设置flag为是否有漏洞的判断条件。
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这个i=5判断有问题，如果i=4存在漏洞时，已经写入了i=i+1，所以当i=5时，就会生成no vulnerable告警，但flag已经变成了true，flag意义已经不存在了，所以应该设置flag为是否有漏洞的判断条件。