To make use files option as string path

[zemd]

If there is only one file to compile, it is useful to omit array notation

[g13013]

This can lead to have an array of array !

Change it to: options.files = [].concat(options.files);

[zemd]

No, it doesn't lead to that.

// input
[].concat([["hello", "world"]])
// output
// [ Array(2) ]

//input
[].concat.apply([], [["hello", "world"]] )
// output
// ["hello", "world"]

[g13013]

You are right 👍, but sorry to insist, I prefer to change it to a simpler form, it confused me, so it will do with others :)

This line will be enough: options.files = options.files && [].concat(options.files) || [];

[zemd]

Your solution also nice, but first you should validate existence of options.files.length to include only array and string.

so it will be:

options.files = options.files && options.files.length && [].concat(options.files) || [];

[g13013]

Sounds very good for me, go ahead 👍

[g13013]

could you make the changes ? or I merge and modify my self ?