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sceraser
commented
Sep 21, 2019
sceraser
commented
Contributor
- 这个PR解答了当前仓库中的题目（机器人会自动判题并合并当前PR）
- 这个PR修复了当前仓库中的一些代码缺陷（机器人不会判题，而是由管理员来处理当前PR）
Contributor
|
🎉 感谢提交Pull Request！请稍等片刻，我们已经将其提交到CI进行检查，一旦有结果会立即通知您！ 我们不鼓励同时打开多个Pull Request，请集中精力于现在的这个Pull Request，谢谢！:pray: |
Contributor
|
恭喜你，你的提交 244463e 已经通过我们的CI检查：Your tests passed on CircleCI! 👍 它会被自动merge后revert。请不要骄傲，继续挑战！ |
blindpirate
reviewed
Sep 24, 2019
| // Arrays.asList() 返回的list是不可以修改的 | ||
| List<Person> l1 = new ArrayList<>(a); | ||
| List<Person> l2 = new ArrayList<>(b); | ||
| l1.retainAll(l2); |
Collaborator
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两个ArrayList做retainAll的效率很低（想一想为什么？），因此这里最好用两个HashSet做retainAll操作，因为毕竟最后还要返回一个HashSet。
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