chore: polish repo

LICENSE

@@ -0,0 +1,21 @@
+MIT License
+
+Copyright (c) 2025 Silverhand, Inc.
+
+Permission is hereby granted, free of charge, to any person obtaining a copy
+of this software and associated documentation files (the "Software"), to deal
+in the Software without restriction, including without limitation the rights
+to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
+copies of the Software, and to permit persons to whom the Software is
+furnished to do so, subject to the following conditions:
+
+The above copyright notice and this permission notice shall be included in all
+copies or substantial portions of the Software.
+
+THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
+IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
+FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
+AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
+LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
+OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
+SOFTWARE.

README.md

@@ -1 +1,33 @@
 # MCP Auth Python SDK
+
+[![GitHub branch check runs](https://img.shields.io/github/check-runs/mcp-auth/python/master)](https://github.com/mcp-auth/python/actions?query=branch%3Amaster)
+[![codecov](https://codecov.io/gh/mcp-auth/python/graph/badge.svg?token=JXZ4C50SCV)](https://codecov.io/gh/mcp-auth/python)
+[![Stable Version](https://img.shields.io/pypi/v/mcp-auth?label=stable)][PyPI Releases]
+[![PyPI - Python Version](https://img.shields.io/pypi/pyversions/mcp-auth)][PyPI]
+[![PyPI - License](https://img.shields.io/pypi/l/mcp-auth)](https://github.com/mcp-auth/python/blob/master/LICENSE)
+
+[Website]: https://mcp-auth.dev/
+[PyPI]: https://pypi.org/project/mcp-auth/
+[PyPI Releases]: https://pypi.org/project/mcp-auth/#history
+
+The MCP specification [requires OAuth 2.1 and other RFCs](https://modelcontextprotocol.io/specification/2025-03-26/basic/authorization) to be implemented for authorization. MCP Auth aims to connect your MCP server to **any** compatible OAuth 2 or OpenID Connect provider, without spending hours on lengthy implementations.
+
+## Get started
+
+### Is my provider supported?
+
+Check out the [MCP-compatible providers](https://mcp-auth.dev/docs/providers-list) to see which providers are supported. It also includes a tool for real-time checking of provider compatibility.
+
+### Installation
+
+```bash
+pip install mcp-auth
+```
+
+Or use your package manager of choice, such as `poetry` or `uv`.
+
+See [the documentation](https://mcp-auth.dev/docs/get-started) for the full guide.
+
+## Join the discussion
+
+Join the [MCP Auth org discussion](https://github.com/orgs/mcp-auth/discussions) to ask questions or share your feedback.

pyproject.toml

@@ -1,17 +1,19 @@
 [project]
 name = "mcpauth"
 version = "0.0.0"
-description = "Connect your MCP server to any eligible OAuth 2 or OpenID Connect provider"
+description = "Plug-and-play auth for Python MCP servers."
 authors = [{ name = "Silverhand Inc.", email = "contact@silverhand.io" }]
 readme = "README.md"
 requires-python = ">=3.9"
-license = { text = "MIT" }
+license = "MIT"
 keywords = [
   "authentication",
   "authorization",
   "mcp",
+  "modelcontextprotocol",
   "oauth2",
   "openid-connect",
+  "oidc",
 ]
 dependencies = [
   "pydantic>=2.11.3",
@@ -38,3 +40,6 @@ dev = [
 [tool.coverage.run]
 branch = true
 source = ["mcpauth"]
+
+[tool.setuptools]
+packages = ["mcpauth"]

samples/server/starlette.py

@@ -6,11 +6,14 @@
 from starlette.middleware import Middleware
 from starlette.responses import JSONResponse
 from starlette.requests import Request
+import os
+
+MCP_AUTH_ISSUER = (
+    os.getenv("MCP_AUTH_ISSUER") or "https://replace-with-your-issuer-url.com"
+)
 
 mcpAuth = MCPAuth(
-    MCPAuthConfig(
-        server=fetch_server_config("https://auth.logto.io/oidc", AuthServerType.OIDC)
-    )
+    MCPAuthConfig(server=fetch_server_config(MCP_AUTH_ISSUER, AuthServerType.OIDC))
 )
 
 protected_app = Starlette(